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X^2+3X=19.84
We move all terms to the left:
X^2+3X-(19.84)=0
We add all the numbers together, and all the variables
X^2+3X-19.84=0
a = 1; b = 3; c = -19.84;
Δ = b2-4ac
Δ = 32-4·1·(-19.84)
Δ = 88.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{88.36}}{2*1}=\frac{-3-\sqrt{88.36}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{88.36}}{2*1}=\frac{-3+\sqrt{88.36}}{2} $
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